Matematik

(7b^-1 - x³)·(7cos(0)³ + 5c) =
(3c^-1 - a³)·(3c^-1 + a³) =
(7x^-1 - cos(π)²)·(3cos(π)^-2 + c^-2) =
(6a² - 5c^-1)·(8b - 6cos(π/2)²) =
(b + 6x²)·(b - 6x²) =
(5b² + 3x)·(5b² - 3x) =
(8a² - 6x²)² =
(8x² + 7b^-1)² =
(3a + 7cos(2π/3)²)·(3a - 7cos(2π/3)²) =
(5c - 7c³)·(8a + 7cos(π/2)) =
(5a³ + 8b^-2)·(7b³ - 7a³) =
(5c² - x²)·(5c² + x²) =
(3b^-1 + b³)·(3b^-1 - b³) =
(6a^-1 - b²)·(c^-2 + 5x^-2) =
(5cos(π)^-2 + 6cos(π/2)^-1)·(5cos(π)^-2 - 6cos(π/2)^-1) =
(a - 7cos(π)^-2)·(8b^-2 - 3c³) =
(5a^-2 - 5c²)·(3a³ - 3c) =
(6x^-2 + 5a^-1)·(5cos(2π/3)² + cos(π)^-1) =
(8cos(π/2)³ - 5c^-2)·(8cos(π/2)³ + 5c^-2) =
(3b - c³)·(3b + c³) =
(6b + cos(π/2)³)·(6b - cos(π/2)³) =
(a³ + 3cos(π))² =
(x^-2 + 8b)² =
(8c^-2 + a³)·(3c + c²) =
(3a + b^-1)·(6c^-2 + 5x³) =