Matematik

(8cos(0)² + 3cos(2π/3))·(8cos(0)² - 3cos(2π/3)) =
(8cos(2π/3) - 5a)·(cos(π)^-1 - 7c^-2) =
(6b³ + 5a^-2)·(6b³ - 5a^-2) =
(7b³ - 7b)·(7b³ + 7b) =
(5c^-2 + 5b^-2)² =
(7c^-1 + 8a)·(a² - 7b^-1) =
(3a^-1 + 8c^-1)·(3b + 5b²) =
(3b + 7a²)·(5cos(0)² - 5x^-2) =
(3x - 3cos(2π/3)^-2)² =
(6cos(π)² - 6a^-1)² =
(a^-1 + 7b^-1)·(5c³ - 6x) =
(6x^-1 + c³)·(7a^-1 + 6cos(π)²) =
(3b² - 6a²)·(3c² - a) =
(3b^-2 + 3cos(π/2)³)² =
(8c³ - 3a³)·(c + 3x) =
(3x³ + a²)·(5b² - 8b) =
(3a^-1 - 7c^-1)·(5x² - 3c) =
(7x^-2 - x)·(7x^-2 + x) =
(7cos(2π/3)^-2 + cos(π/2)^-1)·(8b³ - 8b²) =
(6b^-2 - 8cos(π/2))² =
(3x³ - 5c^-1)·(5cos(2π/3)³ + 7a) =
(3x^-2 - 7b)² =
(5cos(0) + 6a)·(5cos(0) - 6a) =
(5a² - 3cos(π/2)^-1)² =
(8cos(π/2)² - 5x²)² =